Môn Toán Lớp 6: Tìm x: |x+2|=1……………..

$\left|x+2\right|=1$

\(⇒\left[ \begin{array}{l}x+2=-1\\x+2=1\end{array} \right.\) \(⇒\left[ \begin{array}{l}x=-3\\x=-1\end{array} \right.\) 

Vậy $x=-3\quad \mathrm{hoặc}\quad \:x=-1$