Môn Toán Lớp 6: xy-2x-3y=0 giúp mình với

Ta có:

xy-2x-3y=0

=> x(y-2) – 3y + 6 = 6

=> x(y-2) – 3(y-2) = 6

=> (y-2)(x-3) = 6

Ta có bảng sau:

\begin{array}{|c|c|c|}\hline  \text{x-3}& \text{-6}& \text{6}& \text{-3}&\text{3}& \text{-2}&\text{2}& \text{-1}&\text{1}\\\hline  \text{y-2}&\text{-1}&\text{1}& \text{-2}& \text{2}& \text{-3}& \text{3}& \text{-6}&\text{6}\\\hline  \text{x}& \text{-3}&\text{9}& \text{0}&\text{6}& \text{1}& \text{5}&\text{2}&\text{4}\\\hline  \text{y}& \text{1}& \text{3}& \text{0}&\text{4}& \text{-1}&\text{5}& \text{-4}&\text{8}\\\hline\end{array}

Vậy (x;y) in {(-3;1);(9;3);(0;0);(6;4);(1;-1);(5;5);(2;-4);(4;8)}

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