Môn Toán Lớp 7: Tìm các số nguyên n để: 2n-1/ n+8 – n-14/n+8 là số nguyên

(2n-1)/(n+8)-(n-14)/(n+8)

\begin{array}{|c|c|}\hline \text{n+8}&\text{1}&\text{-1}&\text{5}&\text{-5}\\\hline \text{n}&\text{-7}&\text{-9}&\text{-3}&\text{-13}\\\hline\end{array}

Vậy n∈{-7;-9;-3;-13} thì (2n-1)/(n+8)-(n-14)/(n+8)∈Z