Môn Toán Lớp 8: 9(3x-2)-x(2-3x)=0 giup minh voi

9(3x-2)-x(2-3x)=0

=> 9(3x-2)+x(3x-2)=0

=> (9+x)(3x-2)=0

=> [(9+x=0),(3x-2=0):}

=> [(x=-9),(3x=2):}

=>$\left[\begin{matrix} x=-9\\ x=\dfrac{2}{3}\end{matrix}\right.$

Vậy x in {-9; 2/3}